MAXIMUM
HEIGHT


Maximum height of the projectile occurs when the vertical component of velocity (Voy=Vf) becomes zero. Suppose T be the time when the vertical component of velocity reduces to zero and Y=h be the maximum height, then,we have:  
Which is the expression for maximum height  
For latest information , free computer courses and high impact notes visit : www.citycollegiate.com  
HORIZONTAL
RANGE OF PROJECTILE


The horizontal distance covered by the projectile during its complete flight is called its range and is denoted by 'R'. in order to find the range of the projectile we make use of the fact that the total flight requires a time that is t = 2T. As the horizontal component of velocity remains uniform, the range can be determined by  


MAXIMUM
RANGE


The range of a projectile is max. when sin2q is maximum and the max. value of sin2q is unity.  
i.e.
R=R_{max}
if sin2q=1 since horizontal range is R = V_{o}^{2} sin2q/g Therefore, R_{max} = V_{o}^{2} (1)/g R_{max} = V_{o}^{2} /g Since, sin2q=1 2q=sin^{1}(1) 2q=90^{o} q=45^{o} This shows that the projectile must be launched at an angle of 45^{O} to get maximum range. 

For latest information , free computer courses and high impact notes visit : www.citycollegiate.com  