SHAPE OF MOLECULES
 
Explain the geometry of BeCl2 in the light of electron pair repulsion theory
and hybrid orbital model.
 

SHAPE OF BeCl2 IN THE LIGHT OF E.P.R.T:
In BeCl2, Be is the central atom.
Be has two bonding pair with chlorine.
It has no lone pair.
Structure of BeCl2 is linear.
SHAPE OF BeCl2 IN THE LIGHT OF H.O.M:
Be uses its Sp-hybrid orbital in bond making.
These orbital overlap with the orbital of two chlorine atoms to form sigma bonds.
All these atoms are arranged linearly at an angle of 180o.

 

Explain the geometry of H2O in the light of electron pair repulsion theory
and hybrid orbital model.

SHAPE OF H2O IN THE LIGHT OF E.P.R.T:
In H2O, oxygen is the central atom.
Oxygen has two bond pairs.
It has two lone pairs.
The repulsion of the lone pairs and the bonded pairs reduce the angle from 109o to 104.5o.
It has tetrahedral structure.
SHAPE OF H2O IN THE LIGHT OF H.O.M:
In terms of hybrid orbital model, oxygen utilizes two of its Sp3 orbitals to form sigma bonds.
Due to reduced angle in H2O, angular or bent structure is formed.

Explain the geometry of NH3 in the light of electron pair repulsion theory
and hybrid orbital model.
 

SHAPE OF NH3 IN THE LIGHT OF E.P.R.T:
In NH3, N is the central atom.
Nitrogen has three bond pairs.
It has only one lone pair which repels the bonding pairs with the result that angle is reduced from 109o to 107o.
SHAPE OF NH3 IN THE LIGHT OF H.O.M:
In term of H.O.M, nitrogen utilizes three of the four Sp3 orbital to form sigma bonds with three hydrogen atoms.
Its structure is pyramidal with bond angles of 107o.

Explain the geometry of BF3 in the light of electron pair repulsion theory
and hybrid orbital model.
 

SHAPE OF BF3 IN THE LIGHT OF E.P.R.T:
In BF3, boron is the central atom.
It has three electron pairs, geometry of molecules will be trigonal.
The angle between them is 120o.
SHAPE OF BF3 IN THE LIGHT OF H.O.M:
Boron atom undergoes Sp2-hybridization producing three Sp2-orbital.
These orbital are arranged trigonally in one plane

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