VALUE OF R
          In atmp.dm3/mole.k
Consider one mole of an ideal gas at S.T.P.
As we know that at S.T.P. one mole of any gas occupies 22.4dm3 volume.
DATA
T = 0 0C + 273 = 273K P=1 atmp n =1 mole V =22.4 dm3
R = ?
Using ideal gas equation
PV = nRT
R = PV/nT
R =1atmp x 22.4 dm3/1 mole x 273K
R = 0.0821 atmp . dm3/mole .
 
In J/mole.k
        Consider onemole of an ideal gas at S.T.P.
        P=1.01 x 105 N/m2
        T = 0 0C + 273 = 273K
        n =1 mole
        V =22.4 dm3 = 22.4/1000=0.0224 m3
        R =?
        Using ideal gas equation
        PV = nRT
        R=PV/nT
        R = 1.01 x 105 x 0.0224/ 1x 273

        R = 8.31 J/mole K
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