VALUE OF R
	In atmp.dm3/mole.k Consider one mole of an ideal gas at S.T.P. As we know that at S.T.P. one mole of any gas occupies 22.4dm3 volume. DATA T = 0 0C + 273 = 273K P=1 atmp n =1 mole V =22.4 dm3 R = ? Using ideal gas equation PV = nRT R = PV/nT R =1atmp x 22.4 dm3/1 mole x 273K R = 0.0821 atmp . dm3/mole .
	In J/mole.k
	Consider onemole of an ideal gas at S.T.P.         P=1.01 x 105 N/m2         T = 0 0C + 273 = 273K         n =1 mole         V =22.4 dm3 = 22.4/1000=0.0224 m3         R =?         Using ideal gas equation         PV = nRT         R=PV/nT         R = 1.01 x 105 x 0.0224/ 1x 273         R = 8.31 J/mole K
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